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_romantic_鎮(zhèn)木蟲 (著名寫手)
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[求助]
初學(xué)者求助,matlab模仿程序 已有1人參與
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function KineticsEst5 % 動(dòng)力學(xué)ODE方程模型的參數(shù)估計(jì) clear all clc k0 = [0 0 0 0]; % 參數(shù)初值 lb = [ -inf -inf -inf -inf ]; % 參數(shù)下限 ub = [+inf +inf +inf +inf ]; % 參數(shù)上限 x0 = [8.5 28.8 27.6]; tspan=[0 0.222 0.333 0.444]; yexp = [8.5000 28.8000 27.6000 4.8000 23.2000 35.3000 4.2000 21.6000 36.5000 4.0000 21.2000 37.3000]; % yexp: 實(shí)驗(yàn)數(shù)據(jù)[x1 x2 x3] % 使用函數(shù)fmincon()進(jìn)行參數(shù)估計(jì) [k,fval,flag] = fmincon(@ObjFunc4Fmincon,k0,[],[],[],[],lb,ub,[],[],x0,yexp); fprintf('\n使用函數(shù)fmincon()估計(jì)得到的參數(shù)值為:\n') fprintf('\tk1 = %.4f\n',k(1)) fprintf('\tk2 = %.4f\n',k(2)) fprintf('\tk3 = %.4f\n',k(3)) fprintf('\tk4 = %.4f\n',k(4)) fprintf(' The sum of the squares is: %.1e\n\n',fval) k_fmincon = k; % 使用函數(shù)lsqnonlin()進(jìn)行參數(shù)估計(jì) [k,resnorm,residual,exitflag,output,lambda,jacobian] = ... lsqnonlin(@ObjFunc4LNL,k0,lb,ub,[],x0,yexp); ci = nlparci(k,residual,jacobian); fprintf('\n\n使用函數(shù)lsqnonlin()估計(jì)得到的參數(shù)值為:\n') Output % 以函數(shù)fmincon()估計(jì)得到的結(jié)果為初值,使用函數(shù)lsqnonlin()進(jìn)行參數(shù)估計(jì) k0 = k_fmincon; [k,resnorm,residual,exitflag,output,lambda,jacobian] = ... lsqnonlin(@ObjFunc4LNL,k0,lb,ub,[],x0,yexp); ci = nlparci(k,residual,jacobian); fprintf('\n\n以fmincon()的結(jié)果為初值,使用函數(shù)lsqnonlin()估計(jì)得到的參數(shù)值為:\n') Output % ------------------------------------------------------------------ function f = ObjFunc4Fmincon(k,x0,yexp) tspan = [0.00 : 0.01 : 0.44]; [t x] = ode45(@KineticEqs,tspan,x0,[],k); y(:,1:3) = x(:,1:3); f = sum((y(:,1)-yexp(:,1)).^2) + sum((y(:,2)-yexp(:,2)).^2) ... + sum((y(:,3)-yexp(:,3)).^2) ; % 以函數(shù)fmincon()估計(jì)得到的結(jié)果為初值,使用函數(shù)lsqnonlin()進(jìn)行參數(shù)估計(jì) k0 = k_fmincon; [k,resnorm,residual,exitflag,output,lambda,jacobian] = ... lsqnonlin(@ObjFunc4LNL,k0,lb,ub,[],x0,yexp); ci = nlparci(k,residual,jacobian); fprintf('\n\n以fmincon()的結(jié)果為初值,使用函數(shù)lsqnonlin()估計(jì)得到的參數(shù)值為:\n') Output % ------------------------------------------------------------------ function f = ObjFunc4LNL(k,x0,yexp) tspan = [0.00 : 0.01 : 0.44]; [t x] = ode45(@KineticEqs,tspan,x0,[],k); y(:,1:3) = x(:,1:3); f1 = y(:,1) - yexp(:,1); f2 = y(:,2) - yexp(:,2); f3 = y(:,3) - yexp(:,3); f = [f1; f2; f3]; % ------------------------------------------------------------------ function dxdt = KineticEqs(t,x,k) dxdt = ... [ (k(1)*x(2)- k(1)*x(1)) (k(1)*x(2)+(k(3)-k(2)-k(4))*x(3)) (k(3)*x(2)-k(4)*x(3)) ]; |
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程序中的問(wèn)題: 1、tspan = [0.00 : 0.01 : 0.44]與tspan=[0 0.222 0.333 0.444]沒(méi)有對(duì)應(yīng) 2、f = sum((y(:,1)-yexp(:,1)).^2) + sum((y(:,2)-yexp(:,2)).^2) + sum((y(:,3)-yexp(:,3)).^2) 后面的代碼是多余的,計(jì)算的結(jié)果不使用 執(zhí)行結(jié)果: 使用函數(shù)fmincon()估計(jì)得到的參數(shù)值為: k1 = -0.6403 k2 = 1.8125 k3 = 3.6968 k4 = 1.9950 The sum of the squares is: 4.0 |

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